Has anyone got a SuperBASIC routine that will convert a number into the six byte QL Floating Point internal form? Preferably returning a string of 12 Hex digits.
I would like to write a Function to do something like x$=FP$(16453)
Floating point conversion

 Gold Card
 Posts: 276
 Joined: Tue Dec 17, 2013 1:17 pm
Re: Floating point conversion
Something along the lines of (Untested, no QL at hand...)
(i.e. POKE_F and PEEK combined) should work. POKE_F is part of Turbo Toolkit.
Tobias
Code: Select all
x = respr (10)
a = a$ : REMark convert from String to float
POKE_F x, a
FOR i = 1 TO 6
x$ = x$ & HEX$(PEEK (x + i  1), 8)
END FOR i
PRINT X$
(i.e. POKE_F and PEEK combined) should work. POKE_F is part of Turbo Toolkit.
Tobias
Re: Floating point conversion
FLOAT$(<number>)
This function takes a floating point number and returns the
internal math representation of the number as a six character
string.
...in PDTK on Dilwyn's site
This function takes a floating point number and returns the
internal math representation of the number as a six character
string.
...in PDTK on Dilwyn's site
Re: Floating point conversion
Martin_Head wrote:Has anyone got a SuperBASIC routine that will convert a number into the six byte QL Floating Point internal form? Preferably returning a string of 12 Hex digits.
I would like to write a Function to do something like x$=FP$(16453)
If I understood your question correctly, you are looking for something like this?
Code: Select all
100 CLS
110 ovf = 2 ^ 31: REMark Sign switch
120 ofs = $81F: REMark Offset/bias
130 :
140 REMark Test
150 PRINT FLT$(20000)
160 PRINT FLT$(20000)
170 PRINT FLT$(2E6)
180 PRINT FLT$(2E6)
190 PRINT FLT$(2E6)
200 PRINT FLT$(2E6)
210 PRINT FLT$(222.22)
220 PRINT FLT$(222.22)
230 :
240 DEFine FuNction FLT$(n)
250 LOCal x, m, s
260 PRINT n,: rem ### debug
270 IF n = 0: RETurn FILL$('0', 12)
280 IF n < 0 THEN
290 s = 1: m = n
300 ELSE
310 s = 1: m = n
320 END IF
330 :
340 FOR x = ofs TO 0 STEP 1
350 m = m + m
360 IF m >= ovf: EXIT x
370 END FOR x
380 m = m / 2
390 m = s * m
400 PRINT FLT(x, m),: rem ### debug
410 RETurn HEX$(x, 16) & HEX$(m, 32)
420 END DEFine FLT$
430 :
440 DEFine FuNction FLT(x, b)
450 IF b = 0 OR x = 0: RETurn 0
460 RETurn b * 2 ^ (x  ofs)
470 END DEFine FLT
480 :
Its a bit crude, and Im unsure about edge conditions. Also no error trapping.. If you improve it, or find something better, feed it back!
Per
For every complex problem there is an answer that is clear, simple, and wrong.
 H. L. Mencken
For every complex problem there is an answer that is clear, simple, and wrong.
 H. L. Mencken

 Trump Card
 Posts: 160
 Joined: Mon Nov 24, 2014 2:03 pm
Re: Floating point conversion
Hi,
Turbo has a FLOAT$ function, ' which returns a sixcharacter string of the specified floatingpoint number '. See Turbo manual : page 190.
Eg : F$= FLOAT$(PI) : returns 6 ASCII characters ( whose codes are : 8 , 2 , 100 , 135 , 237 , 81 )
Regards,
Steve.
Turbo has a FLOAT$ function, ' which returns a sixcharacter string of the specified floatingpoint number '. See Turbo manual : page 190.
Eg : F$= FLOAT$(PI) : returns 6 ASCII characters ( whose codes are : 8 , 2 , 100 , 135 , 237 , 81 )
Regards,
Steve.

 Trump Card
 Posts: 160
 Joined: Mon Nov 24, 2014 2:03 pm
Re: Floating point conversion
Hi again,
Using Turbo :
100 f$ = FLOAT$(PI) : s$=''
120 for i=1 to 6 : s$=s$ & ( HEX$( CODE( f$(i),8))
130 PRINT s$
Will convert 3.141592654 into 08026487ED51, the HEX value.
Regards,
Steve.
Using Turbo :
100 f$ = FLOAT$(PI) : s$=''
120 for i=1 to 6 : s$=s$ & ( HEX$( CODE( f$(i),8))
130 PRINT s$
Will convert 3.141592654 into 08026487ED51, the HEX value.
Regards,
Steve.
Re: Floating point conversion
Actually my routine above only floats "long integers". This one "floats" floats too:
This is just a rough translation from my assembler original. Im sure there is scope for
optimisation! Or perhaps there is a mathematical solution, without the BASIC loops?
Anyway, since its probably not what you wanted, Martin, it doesnt really matter..
Code: Select all
10 ovf = 2 ^ 30: REMark preSign switch
20 :
..
100 DEFine FuNction FLT$(n)
110 LOCal x, m, s
120 IF n = 0: RETurn FILL$('0', 12)
130 IF n < 0 THEN
140 s = 1: m = n
150 ELSE
160 s = 1: m = n
170 END IF
180 :
190 IF m > ovf THEN
200 FOR x = $81F TO $FFF
210 m = m / 2
220 IF m < ovf: EXIT x
230 END FOR x
240 m = m + m
250 ELSE
260 FOR x = $81F TO 0 STEP 1
270 m = m + m
280 IF m > ovf: EXIT x
290 END FOR x
300 m = m / 2
310 END IF
320 m = s * m
330 RETurn HEX$(x, 16) & HEX$(m, 32)
340 END DEFine FLT$
350 :
This is just a rough translation from my assembler original. Im sure there is scope for
optimisation! Or perhaps there is a mathematical solution, without the BASIC loops?
Anyway, since its probably not what you wanted, Martin, it doesnt really matter..
Per
For every complex problem there is an answer that is clear, simple, and wrong.
 H. L. Mencken
For every complex problem there is an answer that is clear, simple, and wrong.
 H. L. Mencken

 Trump Card
 Posts: 160
 Joined: Mon Nov 24, 2014 2:03 pm
Re: Floating point conversion
Hi Per,
Thanks for your latest code, which I just tested :
Line 10 should read ovf = 2^31 to get a correct answer, (compared to the TURBO example for PI).
But then the routine fails for floats larger than 1E9 ...
The function should operate from 1E616 to 1e615.
I will try to see if I can debug it.
Regards,
Steve.
Thanks for your latest code, which I just tested :
Line 10 should read ovf = 2^31 to get a correct answer, (compared to the TURBO example for PI).
But then the routine fails for floats larger than 1E9 ...
The function should operate from 1E616 to 1e615.
I will try to see if I can debug it.
Regards,
Steve.

 Gold Card
 Posts: 276
 Joined: Tue Dec 17, 2013 1:17 pm
Re: Floating point conversion
Thanks everyone for the replies. I don't really want to go to the trouble of installing a toolkit just for this, So I will probably go for Per's solution.
Martin
Martin

 Trump Card
 Posts: 160
 Joined: Mon Nov 24, 2014 2:03 pm
Re: Floating point conversion
Hi again,
Per's solution needs several tweaks to get all the right answers , (Tested against the TURBo codes I gave).
Line 10 ovf=2^30 is now OK, but :
read 190 If m> (2^31) THEN
delete 270 and 300
read 280 if m>=ovf: exit x: else m=m+m
This now works in the full range of 1E615 to 1E615 !
If you find any further bugs, please let us all know...
Regards,
Steve.
Per's solution needs several tweaks to get all the right answers , (Tested against the TURBo codes I gave).
Line 10 ovf=2^30 is now OK, but :
read 190 If m> (2^31) THEN
delete 270 and 300
read 280 if m>=ovf: exit x: else m=m+m
This now works in the full range of 1E615 to 1E615 !
If you find any further bugs, please let us all know...
Regards,
Steve.
Return to “Software & Programming”
Who is online
Users browsing this forum: No registered users and 7 guests