vanpeebles wrote:This has been a very enjoyable and interesting thread to read

...so far. Please keep it going

vanpeebles wrote:This has been a very enjoyable and interesting thread to read

...so far. Please keep it going

tcat wrote:Your MDV2_ seems on average a bit slower, is that your star performer? Usually it is the drive mounted as MDV1_ , as MDV2_ picks some noise in the QL case, the QL board is a subject to applying the documented mod for better drive performance.

Thanks for your comments.

So did you apply the famous "mandatory modifications" and you got better performance?

Anyway, concerning my straight-edged mdv: when I mounted them in the QL i decided to swap the units (and the shield). So my current mdv2 was originally the mdv1.

I did't pay much attention on which unit got the best performance. Generally speaking I can say that both drives got evident superior results in comparison with the key-edged ones.

I'll do some tests to find out which one is the best then I let you know.

Generally speaking I can say that both drives got evident superior results in comparison with the key-edged ones.

The facts we have learnt about your Iss#5,6 drives:

- all run at the same speed

- all heads have same resistance

- Iss#5 do not have mod applied

- all share same erase current (tested using same QL Iss#6 board)

Cannot comment on inductance, there is a spread of 0.2 measured values.

Cannot comment if your QL board Iss#6 has had MDV mod applied.

Can you comment on motor power leads, if they are laid each from either side of the Iss#5 head board, as shown in RWAPs' pictures?

Tomas

Cristian wrote:concerning my straight-edged mdv: when I mounted them in the QL i decided to swap the units (and the shield). So my current mdv2 was originally the mdv1.

I did't pay much attention on which unit got the best performance. I'll do some tests

After some tests I can say that the best results are averagely obtained with mdv2. I got

tcat wrote:Can you comment on motor power leads, if they are laid each from either side of the Iss#5 head board, as shown in RWAPs' pictures?

Yes the wiring seems to correspond. Please see the pictures I posted:

viewtopic.php?f=2&t=1187&start=20#p19357

I don't think that a so slight speed difference could be sufficient to produce such results.

Consider Loop time formula.

Code: Select all

`LoopTime[s] = TapeLenght[mm] / ( RollerDiameter[mm] * PI) / MotorSpeed [r/m] * 60`

e.g.

5080mm / (6mm *pi) / 2250 * 60 secs/min = 7.19 secs

Where:

2250 - nominal motor speed in [rpm] (revolutions per minute)

5080 - nominal tape length in [mm], 200 inches ~ 5.08 m

6 - roller diameter in [mm]

Consider media Sector count

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`SectorCount[n] = LoopTime[s] * 10^6 / SectorTime[us]`

e.g.

7.19 * 1.000.000 / 31760 = 226,39 ~ 225 + 5% sectors on media

Where:

31760 - sector time in micro seconds [us] (refer to A.C. Dicken's QL Advanced Guide), this is what QL is tuned to.

This gives nominal loop time ~ 7secs

0.25 secs * 10^6 / 31760 ~ 8 sectors.

1/4 of a second then corresponds to 8 sectors on tape, where each sector is 512 byte long.

225 nominal + 8 sectors ~ 232 could this be close to the sectors you see on your tape?

If the above is at all correct, then media density can be expressed as,

1 byte ~ 40 [us] of tape loop time

Cannot believe that 0.00004 of a second can take one byte, that is 8 bits, can it?

Tomas

Cannot believe that 0.00004 of a second can take one byte, that is 8 bits, can it?

Hi,

It possibly can. In summary MD parameters:

Code: Select all

`Sector time [us]: 31760`

Tape length [mm]: 5080 ~ 200"

Loop time [s]: 7,19

Nominal sectors [n]: 225

From the parameters we can calculate, on what tape length one sector will fit.

Code: Select all

`SectorLenght[mm] = TapeLenght[mm] / SectorCount[n]`

5080 / 225 ~ 22.6mm

One sector will fit into roughly one inch of tape.

How much one byte will take then?

Code: Select all

`ByteLenght[mm] = SectorLenght[mm] / BytesPerSector[n]`

22.6 / 512 ~ 0.044mm!

If the above correct then 44 um (microns) of tape must accommodate 8 bits, and that is 2*8 FM transitions, we already learnt.

How could this be at all achieved?

Tomas

Last edited by tcat on Mon Nov 13, 2017 8:38 am, edited 3 times in total.

Technical docs and hardware shows there are 2 heads, so your calculations need to reflect that 2 heads are in use.

Pr0f wrote:Technical docs and hardware shows there are 2 heads, so your calculations need to reflect that 2 heads are in use.

Erm, no. Probably not. There is no mechanism that ever uses the two tracks on the tape

Tobias

Hi,

Yes, that is right!

We have two tracks here of a stereo head (one erase coil is common to both tracks). With a mono head (one track) we would have needed 2x5080mm length of tape, and 2x7.19 secs of loop time to achieve 225 sectors.

I may be wrong, can you please help as to which calculations need correcting with some index of 2?

Thank you.

Tomas

Yes, that is right!

We have two tracks here of a stereo head (one erase coil is common to both tracks). With a mono head (one track) we would have needed 2x5080mm length of tape, and 2x7.19 secs of loop time to achieve 225 sectors.

I may be wrong, can you please help as to which calculations need correcting with some index of 2?

Thank you.

Tomas

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